Партнерка на США и Канаду по недвижимости, выплаты в крипто
- 30% recurring commission
- Выплаты в USDT
- Вывод каждую неделю
- Комиссия до 5 лет за каждого referral
Partial Restriction Enzyme Digestion
(Key)
Restriction Map Construction
Explanations:
Clues & Tricks
for a successful Map Construction
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
A) 1 B 1 B 1 B 10 B 1 B 5
B) 1 B 10 B 1 B 1 B 1 B 5
C) 1 B 10 B 1 B 5 B 1 B 1
D) 1 B 1 B 10 B 1 B 1 B 5
E) 1 B 10 B 5 B 1 B1 B 1
F) 10 B 1 B 1 B 1 B 1 B 5
??Which one of the above is the correct Map???
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
Clues 1:
BamH1 (Complete digestion) = 1, 5, 10 kb
1 + 5 + 10 = 16 not 19 kb, imply some missing fragments.
BamH1 (Complete digestion) = 1, 5, 10, [1, 1, 1] kb
Clues 2:
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
Fragment 10 (Frag.10) cannot be at the end of the map, since there is no Fragment 9 in the Partial digestion data. [19 minus 10 = 9], imply linear map
*** If some fragment cannot be at the end, imply that the map have to be Linear.
**** If all fragments can be at the end, imply the Map have to be Circular.
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
A) 1 B 1 B 1 B 10 B 1 B 5
Reasoning:
A) cannot be the right map, because there you cannot get Pratial Frag. 7 from this map. Yet there is Frag. 7 in the Partial Digest data.
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
C) 1 B 10 B 1 B 5 B 1 B 1
Reasoning:
C) cannot be the right map, because you cannot get a partial fragment of 3 from this Map.
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
D) 1 B 1 B 10 B 1 B 1 B 5
Reasoning:
D) cannot be the right map, because you cannot got Partial Frag. 3.from this map.
Imply the three Frag.1 have to be next to each other in the correct map.
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
E) 1 B 10 B 5 B 1 B1 B 1
Reasoning:
Map E cannot be the right one, because there is no Fragment 15 in the Partial Digest data.
Imply Frag.10 & Frag 5 cannot be next to each other in the correct map.
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
F) 10 B 1 B 1 B 1 B 1 B 5
Reasoning:
F) cannot be the right map, because there is no Frag. 4 in the Partial Digest data.
Imply the four Frag 1 cannot be together in the correct map.
Construct Restriction Map(s) base on the following Partial Digestion data using BamH1:
Uncut: 19 kb
BamH1 (Complete digestion) = 1, 5, 10 kb
BamH1 (Partial digestion) =1, 2, 3, 5, 6, 7, 8, 10, 11, 12, 13, 14, 18, 19 kb
Map B is the correct Map
B) 1 B 10 B 1 B 1 B 1 B 5
Clues:
- Frag.10 cannot be at the end (since no Frag.9 in Partial digest data). Also, it imply a linear map. Frag10 & Farg.5 cannot be together (no 15 in Partial) The three Frag.1 have to be together to get Frag.3
